/usr/lib/python3/dist-packages/fontTools/svgLib/path/__init__.py is in python3-fonttools 3.21.2-1.
This file is owned by root:root, with mode 0o644.
The actual contents of the file can be viewed below.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 | from __future__ import (
print_function, division, absolute_import, unicode_literals)
from fontTools.misc.py23 import *
from fontTools.pens.transformPen import TransformPen
from .parser import parse_path
try:
from xml.etree import cElementTree as ElementTree # python 2
except ImportError: # pragma nocover
from xml.etree import ElementTree # python 3
__all__ = [tostr(s) for s in ("SVGPath", "parse_path")]
class SVGPath(object):
""" Parse SVG ``path`` elements from a file or string, and draw them
onto a glyph object that supports the FontTools Pen protocol.
For example, reading from an SVG file and drawing to a Defcon Glyph:
import defcon
glyph = defcon.Glyph()
pen = glyph.getPen()
svg = SVGPath("path/to/a.svg")
svg.draw(pen)
Or reading from a string containing SVG data, using the alternative
'fromstring' (a class method):
data = '<?xml version="1.0" ...'
svg = SVGPath.fromstring(data)
svg.draw(pen)
Both constructors can optionally take a 'transform' matrix (6-float
tuple, or a FontTools Transform object) to modify the draw output.
"""
def __init__(self, filename=None, transform=None):
if filename is None:
self.root = ElementTree.ElementTree()
else:
tree = ElementTree.parse(filename)
self.root = tree.getroot()
self.transform = transform
@classmethod
def fromstring(cls, data, transform=None):
self = cls(transform=transform)
self.root = ElementTree.fromstring(data)
return self
def draw(self, pen):
if self.transform:
pen = TransformPen(pen, self.transform)
for el in self.root.findall(".//{http://www.w3.org/2000/svg}path[@d]"):
parse_path(el.get("d"), pen)
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